hist {graphics} | R Documentation |
The generic function hist
computes a histogram of the given
data values. If plot=TRUE
, the resulting object of
class "histogram"
is plotted by
plot.histogram
, before it is returned.
hist(x, ...)
## Default S3 method:
hist(x, breaks = "Sturges",
freq = NULL, probability = !freq,
include.lowest = TRUE, right = TRUE,
density = NULL, angle = 45, col = NULL, border = NULL,
main = paste("Histogram of" , xname),
xlim = range(breaks), ylim = NULL,
xlab = xname, ylab,
axes = TRUE, plot = TRUE, labels = FALSE,
nclass = NULL, ...)
x |
a vector of values for which the histogram is desired. |
breaks |
one of:
In the last three cases the number is a suggestion only. |
freq |
logical; if |
probability |
an alias for |
include.lowest |
logical; if |
right |
logical; if |
density |
the density of shading lines, in lines per inch.
The default value of |
angle |
the slope of shading lines, given as an angle in degrees (counter-clockwise). |
col |
a colour to be used to fill the bars.
The default of |
border |
the color of the border around the bars. The default is to use the standard foreground color. |
main , xlab , ylab |
these arguments to |
xlim , ylim |
the range of x and y values with sensible defaults.
Note that |
axes |
logical. If |
plot |
logical. If |
labels |
logical or character. Additionally draw labels on top
of bars, if not |
nclass |
numeric (integer). For S(-PLUS) compatibility only,
|
... |
further arguments and graphical parameters passed to
|
The definition of histogram differs by source (with
country-specific biases). R's default with equi-spaced breaks (also
the default) is to plot the counts in the cells defined by
breaks
. Thus the height of a rectangle is proportional to
the number of points falling into the cell, as is the area
provided the breaks are equally-spaced.
The default with non-equi-spaced breaks is to give a plot of area one, in which the area of the rectangles is the fraction of the data points falling in the cells.
If right = TRUE
(default), the histogram cells are intervals
of the form (a, b]
, i.e., they include their right-hand endpoint,
but not their left one, with the exception of the first cell when
include.lowest
is TRUE
.
For right = FALSE
, the intervals are of the form [a, b)
,
and include.lowest
means ‘include highest’.
A numerical tolerance of 10^{-7}
times the median bin size
is applied when counting entries on the edges of bins.
The default for breaks
is "Sturges"
: see
nclass.Sturges
. Other names for which algorithms
are supplied are "Scott"
and "FD"
/
"Freedman-Diaconis"
(with corresponding functions
nclass.scott
and nclass.FD
).
Case is ignored and partial matching is used.
Alternatively, a function can be supplied which
will compute the intended number of breaks as a function of x
.
an object of class "histogram"
which is a list with components:
breaks |
the |
counts |
|
density |
values |
intensities |
same as |
mids |
the |
xname |
a character string with the actual |
equidist |
logical, indicating if the distances between
|
Becker, R. A., Chambers, J. M. and Wilks, A. R. (1988) The New S Language. Wadsworth & Brooks/Cole.
Venables, W. N. and Ripley. B. D. (2002) Modern Applied Statistics with S. Springer.
nclass.Sturges
, stem
,
density
, truehist
in package MASS.
Typical plots with vertical bars are not histograms. Consider
barplot
or plot(*, type = "h")
for such bar plots.
op <- par(mfrow=c(2, 2))
hist(islands)
utils::str(hist(islands, col="gray", labels = TRUE))
hist(sqrt(islands), breaks = 12, col="lightblue", border="pink")
##-- For non-equidistant breaks, counts should NOT be graphed unscaled:
r <- hist(sqrt(islands), breaks = c(4*0:5, 10*3:5, 70, 100, 140),
col='blue1')
text(r$mids, r$density, r$counts, adj=c(.5, -.5), col='blue3')
sapply(r[2:3], sum)
sum(r$density * diff(r$breaks)) # == 1
lines(r, lty = 3, border = "purple") # -> lines.histogram(*)
par(op)
require(utils) # for str
str(hist(islands, breaks=12, plot= FALSE)) #-> 10 (~= 12) breaks
str(hist(islands, breaks=c(12,20,36,80,200,1000,17000), plot = FALSE))
hist(islands, breaks=c(12,20,36,80,200,1000,17000), freq = TRUE,
main = "WRONG histogram") # and warning
require(stats)
set.seed(14)
x <- rchisq(100, df = 4)
## Comparing data with a model distribution should be done with qqplot()!
qqplot(x, qchisq(ppoints(x), df = 4)); abline(0,1, col = 2, lty = 2)
## if you really insist on using hist() ... :
hist(x, freq = FALSE, ylim = c(0, 0.2))
curve(dchisq(x, df = 4), col = 2, lty = 2, lwd = 2, add = TRUE)