This help topic is for R version 2.9.0. For the current version of R, try https://stat.ethz.ch/R-manual/R-patched/library/stats/html/dendrapply.html
dendrapply {stats}R Documentation

Apply a Function to All Nodes of a Dendrogram

Description

Apply function FUN to each node of a dendrogram recursively. When y <- dendrapply(x, fn), then y is a dendrogram of the same graph structure as x and for each node, y.node[j] <- FUN( x.node[j], ...) (where y.node[j] is an (invalid!) notation for the j-th node of y.

Usage

dendrapply(X, FUN, ...)

Arguments

X

an object of class "dendrogram".

FUN

an R function to be applied to each dendrogram node, typically working on its attributes alone, returning an altered version of the same node.

...

potential further arguments passed to FUN.

Value

Usually a dendrogram of the same (graph) structure as X. For that, the function must be conceptually of the form FUN <- function(X) { attributes(X) <- .....; X }, i.e. returning the node with some attributes added or changed.

Note

this is still somewhat experimental, and suggestions for enhancements (or nice examples of usage) are very welcome.

Author(s)

Martin Maechler

See Also

as.dendrogram, lapply for applying a function to each component of a list, rapply for doing so to each non-list component of a nested list.

Examples

require(graphics)

## a smallish simple dendrogram
dhc <- as.dendrogram(hc <- hclust(dist(USArrests), "ave"))
(dhc21 <- dhc[[2]][[1]])

## too simple:
dendrapply(dhc21, function(n) utils::str(attributes(n)))

## toy example to set colored leaf labels :
local({
  colLab <<- function(n) {
      if(is.leaf(n)) {
        a <- attributes(n)
        i <<- i+1
        attr(n, "nodePar") <-
            c(a$nodePar, list(lab.col = mycols[i], lab.font= i%%3))
      }
      n
  }
  mycols <- grDevices::rainbow(attr(dhc21,"members"))
  i <- 0
 })
dL <- dendrapply(dhc21, colLab)
op <- par(mfrow=2:1)
 plot(dhc21)
 plot(dL) ## --> colored labels!
par(op)

[Package stats version 2.9.0 ]