Replace a subset of a brdr object

# S3 method for brdr
[(x, ...) <- value

Arguments

x

A brdr object.

...

Indices.

value

A brdr() object, number or matrix.

Value

A brdr() object.

Details

You probably don't need to call this directly. If you want to access border thicknesses, do e.g.

l_borders &lt;- brdr_thickness(left_border(ht))

which will give you a matrix of numbers.